how does 4/3*(3.0*10^-3)^3 become 1.1 x 10^-7)?
\(\frac{4}{3}*(3.0*10^{-3})^3\\ =\frac{4}{3}*3^3*10^{-9}\\ =4*3^2*10^{-9}\\ =4*9*10^{-9}\\ =36*10^{-9}\\ =3.6*10^{+1}*10^{-9}\\ =3.6*10^{-8}\\\)
So no, i guess it does not :))
It doesn't.....
4/3*(3.0*10^-3)^3 =
(4/3)(3^3 * 10^-9) =
[ 4 * 3^3] / 3 * 10^-9 =
4*3^2 * 10^-9 =
4 * 9 * 10^-9 =
36 * 10^-9 =
3.6 * 10^-8
