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A ski slope falls a vertical height of 550 metres for a distance of 1750 m traveled down the ski hill. What is the measure of angle θ to the nearest degree?

 Aug 13, 2015

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 #1
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I assume you want the angle of elevation at the bottom of the hill....We can use the sine inverse to find this....we have........

 

sine-1 (550 /1750) = about 18.3°  = 18°   (to the nearest degree)

 

 

 

 Aug 13, 2015
 #1
avatar+130516 
+5
Best Answer

I assume you want the angle of elevation at the bottom of the hill....We can use the sine inverse to find this....we have........

 

sine-1 (550 /1750) = about 18.3°  = 18°   (to the nearest degree)

 

 

 

CPhill Aug 13, 2015

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