A(t)=Ie^rt
A(t)=75e^(-1.2)
A(t)=75(0.301194)
A(t)=22.59
How is this the answer? I'm plugging it into my calculator and I'm confused if I'm doing it wrong. Please help. What does "e" even represent?
+33661 e is a number approximately equal to 2.71828, though its decimal expansion is infinitely long.
It can be expressed as (for example):
$$e=\sum_{n=0}^\infty\frac{1}{n!}=1 + \frac{1}{1}+\frac{1}{1*2}+\frac{1}{1*2*3}+...$$
or
$$e=\lim_{n\rightarrow \infty}(1+\frac{1}{n})^n$$
In your case you have A(t) = I*ert where I and r must be known constants (I = 75).
Your next lines shouldn't have A(t), but should have A(a specific time such that r*this time = -1.2).
.
+130511 "e" is the natural log base = the irrational number 2.718............
So e^(-1.2) = about 0.3011942119122021
And multiplying this by 75 = about 22.589 = about 22.59
+118723 A(t)=Ie^rt
What are your values for t, l, and r ?
I assume l is 75 what about t and r
+33661 e is a number approximately equal to 2.71828, though its decimal expansion is infinitely long.
It can be expressed as (for example):
$$e=\sum_{n=0}^\infty\frac{1}{n!}=1 + \frac{1}{1}+\frac{1}{1*2}+\frac{1}{1*2*3}+...$$
or
$$e=\lim_{n\rightarrow \infty}(1+\frac{1}{n})^n$$
In your case you have A(t) = I*ert where I and r must be known constants (I = 75).
Your next lines shouldn't have A(t), but should have A(a specific time such that r*this time = -1.2).
.
