A tractor has a rear wheel with a circumference of x m. The circumference of the front wheel is 6 m less. If the front wheel makes 10 more revolutions than the rear wheel every 360m, what is the circumference in m of the front wheel?
Let the circumference of the rear wheel =C The circumference of the front wheel =C - 6 360 / [10*(C - 6)] =360 / C, solve for C C = 6 2/3 - meters - circum. of rear wheel. 6 2/3 - 6 =2/3 - meters - circum. of front wheel.