A triangle has vertices of P, Q , R
The coordinates of P are (-3, -6)
The coordinates of Q are (1, 4)
The coordinates of R are (5, -2)
M is the midpoint of PQ
N is the midpoint of QR
Prove that MN is parallel to PR
show your working out
First, you start with writing out the triangle and the givens.
Angle Q = Angle Q -> Angles equal themselves
QM congruent QP -> QM is half of QP since M is the midpoint, so they're congruent
QN congruent QR -> Same reason as one above
Triangle QMN congruent Triangle QPR -> SAS
MN || PR -> Same Side Rule (Forgot what it's called exactly)
There ya have it
Those are some pretty diagrams, CoopTheDupe!
I am fairly certain that you were referring to the Triangle Proportionality Theorem when you stated "MN || PR -> Same Side Rule (Forgot what it's called exactly)"