a vertical pile of mass 200kg is driven 100mm into the ground by the b**w of 1 tonne hammer which falls through 1.25 m a) calculate velocity of hammer before impact b) calculate momentum before impact c) calculate the momentum of the hammer and pile immediatley after impact assuming they remain in contact
+33654 Assuming potential energy of hammer gets turned into kinetic energy as it hits the mass, we have:
a) (1/2)*1000*v2 = 1000*9.81*1.25 (noting that 1 tonne = 1000kg)
v = √(2*9.81*1.25)
b) momentum = mass*velocity so
mtm = 1000*v
c) This time the masses add, so
mtm = (1000 + 200)*v
You can crunch the numbers.
.
+33654 Assuming potential energy of hammer gets turned into kinetic energy as it hits the mass, we have:
a) (1/2)*1000*v2 = 1000*9.81*1.25 (noting that 1 tonne = 1000kg)
v = √(2*9.81*1.25)
b) momentum = mass*velocity so
mtm = 1000*v
c) This time the masses add, so
mtm = (1000 + 200)*v
You can crunch the numbers.
.
