How would I find the roots of 
, without using the quadratic formula?
So far I have, , how do I return it to it's factored form?
+118696 9x2−6x+1=649x2−6x−63=03(3x2−2x−21)=03x2−2x−21=0
You need 2 numbers that multiply to -3*21=-63 and add to -2
That is really easy.
One has to be neg and the other positive (since they mult to a neg)
The bigger one is the neg one because that add to a neg.
there absolute value is only 2 apart.
So
they are -9 and +7
write -2x as -9x+7x
3x2−2x−21=03x2−9x+7x−21=0$nowfactorinpairs$3x(x−3)+7(x−3)=0(3x+7)(x−3)=03x+7=0orx−3=0x=−7/3orx=+3$slightcorrectionhere−thanksAlan:)$
.+118696 9x2−6x+1=649x2−6x−63=03(3x2−2x−21)=03x2−2x−21=0
You need 2 numbers that multiply to -3*21=-63 and add to -2
That is really easy.
One has to be neg and the other positive (since they mult to a neg)
The bigger one is the neg one because that add to a neg.
there absolute value is only 2 apart.
So
they are -9 and +7
write -2x as -9x+7x
3x2−2x−21=03x2−9x+7x−21=0$nowfactorinpairs$3x(x−3)+7(x−3)=0(3x+7)(x−3)=03x+7=0orx−3=0x=−7/3orx=+3$slightcorrectionhere−thanksAlan:)$
