−x(2ln(x)+1), x=1/(e)^(1/2)
x(2ln(x)+1), x=1/(e)^(1/2)
x(2ln(x)+1),x=1/(e)1/2=e−0.5=e−0.5(2lne−0.5+1)=e−0.5((2∗−0.5)lne+1)=e−0.5((−1)∗1+1)=e−0.5(0)=0