−x(2ln(x)+1), x=1/(e)^(1/2)
x(2ln(x)+1), x=1/(e)^(1/2)
\(x(2ln(x)+1),\qquad x=1/(e)^{1/2}=e^{-0.5}\\ =e^{-0.5}(2lne^{-0.5}+1)\\ =e^{-0.5}((2*-0.5)lne+1)\\ =e^{-0.5}((-1)*1+1)\\ =e^{-0.5}(0)\\ =0 \)