ab+cd-ac-bd=
You cannotr simplify this
But
you can factorise it
ab+cd-ac-bd
=ab-ac+cd-bd
=a(b-c)+d(c-b)
=a(b-c)-d(b-c)
= (a-d)(b-c)
Simplify the following: a b+c d-a c-b d
Factor terms by grouping. a b+c d-a c-b d = (a b-a c)+(c d-b d) = a (b-c)-d (b-c): a (b-c)-d (b-c)
Factor b-c from a (b-c)-d (b-c): Answer: | (b-c) (a-d)
