ABCD is a regular tetrahedron (right pyramid whose faces are all equilateral triangles). If M is the midpoint of CD, then what is cos ABM?

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ABCD is a regular tetrahedron (right pyramid whose faces are all equilateral triangles). If M is the midpoint of CD, then what is cos ABM?

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cos ABM = 2/5.

Guest Dec 8, 2019

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