l ( 5 - 2x) / ( x + 2) l < 1
Set this up as
-1 < (5-2x) / ( x + 2) < 1
We have two inequalities
-1 < ( 5 - 2x) / (x + 2) also (5-2x) / ( x + 2) < 1
-1 ( x + 2) < 5 - 2x 5 - 2x < 1 (x + 2)
-1x -2 < 5 - 2x 5 - 2x < x + 2
x < 5 + 2 5 - 2 < x + 2x
x < 7 3 < 3x
3/3 < x
1 < x ⇒ x > 1
The solution interval is
1 < x < 7