Given that x < 5, rewrite 8x + 5 - |x - 5| without using absolute value signs.
If x < 5 then x - 5 < 0 and |x - 5| = -(x - 5) = -x + 5
8x + 5 - |x - 5| = 8x + 5 - (-x + 5) = 8x + 5 + x - 5 = 9x
