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Pure acid is to be added to a 10% acid solution to obtain 90L of 58% solution. What amounts of each should be used? How many of 100% pure acid should be used to make the solution?

 Feb 10, 2021
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Pure  acid   =100%  acid  =  1

 

So...let  x  be the amout of pure acid to  be added and we  have that

 

1x +.10 *( 90 - x)  =  ( .58)(90)

 

x  + 9  - .10x  =  52.2

 

.90x  =  52.2  - 9

 

.90x  =  43.2      divide both sides by  .90

 

x  = 43.2  / .90  =  48   L

 

 

cool cool cool

 Feb 10, 2021

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