+0  
 
0
44
1
avatar

A 3% solution of sulfuric acid was mixed with an 18% solution of sulfuric acid to produce an 8%solution. How much 3% solution and how much 18% solution were used to produce 15 L of 8% solution?

 Mar 11, 2021
 #1
avatar+30791 
+1

18% = x              acid content   = .18x

3%  = 15-x          acid content  = .03(15-x)

 

 

.18x  + .03(15.x)      =     .08(15)

 

18x    + 3 (15-x) = 8(15)

15x = 75

x = 5 L of 18%      10 L of 3%

 Mar 11, 2021

21 Online Users

avatar
avatar