+0  
 
+10
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avatar+8581 

Which of the following is a root of the polynomial 2x2 – 6x + 3?

A. € 6 + 30 4 B. € 3+ 3 2 C. € 6 + 3i 2 4 D. € 3+ 3

 Jan 26, 2016

Best Answer 

 #4
avatar+128731 
+10

2x^2 – 6x + 3

 

Using the Quad Formula where   a = 2, b = -6 and c = 3, we have

 

[ -(-6)  plus/minus  sqrt [ (-6)^2 - 4(2)(3]  / [ 2(2)]  =

 

[ 6  plus/minus sqrt [ 36 - 24] / [2*2] =

 

[6 plus/minus sqrt (12)] / [2*2]  =

 

[3 plus/minus sqrt(3)] / [2]  =

 

[3 + sqrt(3)] / 2   →   (B)

 

 

cool cool cool

 Jan 26, 2016
edited by CPhill  Jan 26, 2016
 #1
avatar+8581 
+5

Sorry.. The answer's look terrible! I'll fix them (:

 

A. 6 + square root 30

-----------------------------

                 4

 

B. 3 + Square root 3

-----------------------------

                   2

 

C. 6+3i Square root 2

------------------------------

                  4

 

D. 3 + Square root 3

 

E. -3 + square root 3

----------------------------

               2

 

 

Better :)

 Jan 26, 2016
 #2
avatar
+10

If you use the Quadratic Formula you'll wid up with

 

(6 +-  2sqrt3)/4     =    (3 +-sqrt3)/2      So 'B' is one of the roots

 

 

~jc

 Jan 26, 2016
 #3
avatar+4082 
0

Why dontcha make an account jc?

 Jan 26, 2016
 #4
avatar+128731 
+10
Best Answer

2x^2 – 6x + 3

 

Using the Quad Formula where   a = 2, b = -6 and c = 3, we have

 

[ -(-6)  plus/minus  sqrt [ (-6)^2 - 4(2)(3]  / [ 2(2)]  =

 

[ 6  plus/minus sqrt [ 36 - 24] / [2*2] =

 

[6 plus/minus sqrt (12)] / [2*2]  =

 

[3 plus/minus sqrt(3)] / [2]  =

 

[3 + sqrt(3)] / 2   →   (B)

 

 

cool cool cool

CPhill Jan 26, 2016
edited by CPhill  Jan 26, 2016
 #5
avatar+8581 
0

Yeah :D

2. I didn;t know i could use the Quadratic formula

 Jan 26, 2016

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