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cube root of 27xsquared y squared

 Feb 20, 2016
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\(\sqrt[y]{x}=x^\frac{1}{y} \\ \sqrt[3]{27x^2y^2}=\sqrt[3]{3^3x^2y^2}=3^\frac33 \sqrt[3]{x^2y^2}=3\sqrt[3]{x^2y^2}\)

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 Feb 20, 2016

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