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add or subtract the given expressions, simplifying each result and note the combined excluded values.

 

1. ((x-2) / (x+2))+(1 / (x2 -4))-((x+2) / (2-x))

 

2. ((x-3) / (x+3))-(1 / (x-3))+((x+2) / (3-x))

 Oct 26, 2015
 #1
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   1. ((x-2) / (x+2))+(1 / (x2 -4))-((x+2) / (2-x))=(2x^2+9)/(x^2-4)

   2. ((x-3) / (x+3))-(1 / (x-3))+((x+2) / (3-x))=-(12x)/(x^2-9)

 Oct 26, 2015
 #2
avatar+118723 
+5

\(1.\\ \frac{(x-2) }{ (x+2)}+\frac{1 }{ (x^2 -4)}-\frac{(x+2) }{ (2-x)}\\ =\frac{(x-2)(x-2) }{ (x+2)(x-2)}+\frac{1 }{ (x-2)(x+2)}-\frac{(x+2)(x+2) }{ (2-x)(x+2)}\\ =\frac{(x-2)(x-2)\;\;+1\;\;-[ (x+2)(x+2)]}{ (x+2)(x-2)}\\ =\frac{(x^2-4x+4)\;\;-[ x^2+4x+4]\;\;+1}{ (x+2)(x-2)}\\ =\frac{(x^2-4x+4)\;\;+[- x^2-4x-4]\;\;+1}{ (x+2)(x-2)}\\ =\frac{x^2-4x+4- x^2-4x-4\;\;+1}{ (x+2)(x-2)}\\ =\frac{-8x\;\;+1}{ (x+2)(x-2)}\\ =\frac{1-8x}{ x^2-4}\\ =\frac{8x-1}{4- x^2}\\\)

 

You can try the second one yourself. :)

 Oct 27, 2015

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