2e^(x+2)-5=15
Solve for x over the real numbers: 2 e^(x+2)-5 = 15 Add 5 to both sides: 2 e^(x+2) = 20 Divide both sides by 2: e^(x+2) = 10 Take the natural logarithm of both sides: x+2 = log(10) Subtract 2 from both sides: Answer: | x = log(10) - 2