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An equilateral triangle ABC is inscribed in the ellipse x^2/a^2+y^2/b^2=1, so that B is at (0,b), and line AC is parallel to the x-axis, as shown above. Also, foci F_1 and F_2 lie on sides line BC and line AB, respectively. Determine the value of AB/(length between F_1 and F_2). 

 Aug 30, 2020
 #1
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AB/F_1 F_2 works out to 7/4.

 Aug 30, 2020

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