Solve the equation 12x^{2 }-7x+1=0 by fatorising the LHS(lefthandside)

Can someone help please?

Guest Jan 5, 2018

#1**+1 **

12x^{2} -7x+1=0 → (4x - 1)(3x - 1)

Note that the constants must both be +1 or -1, and since the -7x term is negative they must both be -1. Also the factors of 12 must sum to 7. This means only 3 and 4 will do.

The solutions are therefore given by 4x -1 = 0 or x = 1/4 and 3x - 1 = 0 or x = 1/3

Alan
Jan 5, 2018

#1**+1 **

Best Answer

12x^{2} -7x+1=0 → (4x - 1)(3x - 1)

Note that the constants must both be +1 or -1, and since the -7x term is negative they must both be -1. Also the factors of 12 must sum to 7. This means only 3 and 4 will do.

The solutions are therefore given by 4x -1 = 0 or x = 1/4 and 3x - 1 = 0 or x = 1/3

Alan
Jan 5, 2018