How to solve w^2-4w+11? Solve for w. Use completing the square. Simplest radical form.
Solve for w:
w^2-4 w+11 = 0
Subtract 11 from both sides:
w^2-4 w = -11
Add 4 to both sides:
w^2-4 w+4 = -7
Write the left hand side as a square:
(w-2)^2 = -7
Take the square root of both sides:
w-2 = i sqrt(7) or w-2 = -i sqrt(7)
Add 2 to both sides:
w = 2+i sqrt(7) or w-2 = -i sqrt(7)
Add 2 to both sides:
Answer: |w = 2+i sqrt(7) or w = 2-i sqrt(7)
