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Jerry is presently twice as old as his brother and six years older than his sister. How many years from now will Jerry's age be $\frac{2}{3}$ of the combined ages of his brother and sister at that time?

Feb 22, 2021

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Jerry =J
His brother =1/2J
His sister =J - 6
[J/2 + J - 6] = J  multiply both sides by 2
[J + 2J - 12] =2J
3J - 12 = 2J

J = 12 years of age
12 * 1/2 =6 years - his brother's age
12 - 6 = 6 years his sister's age.

Y = Years from now.
2/3[6 + Y + 6 + Y] =12 + Y
Y = 12 years from now when:

Jerry will be =12 + 12 = 24 years of age
His brother =6 + 12 = 18 years of age
His sidter =6 + 12 =18 years of age.
Check: 2/3 * [18 + 18] = 24 Jerry's age 12 years from now.

Feb 22, 2021