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avatar+147 

The sum of three numbers a, b, and c is 99. If we increase a by 6, decrease b by 6 and multiply c by 5, the three resulting numbers are equal. What is the value of b?

 Feb 24, 2021
 #1
avatar+421 
+1

$a+6=b-6=5c\implies a=b-12, c=\frac{b-6}{5}$

$a+b+c=99\implies b-12+b+\frac{b-6}{5}=99\implies \frac{11}{5}b-\frac{66}{5}=99\implies \frac{1}{5}b-\frac{6}{5}=9\implies b-6=45\implies b=\boxed{51}$.

 Feb 24, 2021
 #2
avatar+112966 
0

Please try and refrain from giving full answers. 

Sometimes is ok but many people are here solely to cheat.  Clair is definitely one of those people.

 Feb 24, 2021

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