After falling off a fruit display, a 0.500 kg grapefruit rolls along the floor with a velocity of 1.4 m/s. The grapefruit's kinetic energy i

Kinetic energy is (1/2)*mass*velocity²

$${\mathtt{ke}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{0.5}}{\mathtt{\,\times\,}}{{\mathtt{1.4}}}^{{\mathtt{2}}} \Rightarrow {\mathtt{ke}} = {\mathtt{0.49}}$$

The kinetic energy is 0.49 joules