The ages of Garry,Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest . Three years from now, Gary's age will be 8 less than twice Greggy's age. What are their present ages?
The ages of Garry,Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest . Three years from now, Gary's age will be 8 less than twice Greggy's age. What are their present ages?
Let Gary's age 3 years from now be G
Let Greggy's age 3 years from now be g, then we have:
2g - G=8
There are many solutions to this, but only ONE that meets above conditions, namely,
Greggy's age=12 - 3=9 years, today
Garry's age =16 - 3=13 years, today
Gerry's age =11 years, today
So, 9, 11, 13 are their ages today.
The ages of Garry,Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest . Three years from now, Gary's age will be 8 less than twice Greggy's age. What are their present ages?
Let Gary's age 3 years from now be G
Let Greggy's age 3 years from now be g, then we have:
2g - G=8
There are many solutions to this, but only ONE that meets above conditions, namely,
Greggy's age=12 - 3=9 years, today
Garry's age =16 - 3=13 years, today
Gerry's age =11 years, today
So, 9, 11, 13 are their ages today.
