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Agents J and K work in a long hallway with 4000 equally-spaced, consecutive offices. The agents decide to walk toward each other so they can meet and have lunch together. Agent J has recently been relocated from office 2013 to office 1. His former office neighbor, agent K, is still in office 2014. Assuming that Agent J can walk at a rate of 25 offices per minute, and Agent K walks at 36 offices per minute, what office will they meet at if they leave at the same time?

 Jul 27, 2015

Best Answer 

 #1
avatar+128401 
+5

There are  (2014 - 1) - 1 = 2012 offices between them

 

Each minute they close the distance by (25 + 36) = 61 offices.  So....the number of minutes required to close the whole distance is just  2012/61 = about 33 minutes

 

So   1 + 25(33)  = 826    ....and office 826 is approximately where they meet

 

Proof [ from the other end]..... 2014 - 36(33) =  826

 

 

  

 Jul 27, 2015
 #1
avatar+128401 
+5
Best Answer

There are  (2014 - 1) - 1 = 2012 offices between them

 

Each minute they close the distance by (25 + 36) = 61 offices.  So....the number of minutes required to close the whole distance is just  2012/61 = about 33 minutes

 

So   1 + 25(33)  = 826    ....and office 826 is approximately where they meet

 

Proof [ from the other end]..... 2014 - 36(33) =  826

 

 

  

CPhill Jul 27, 2015

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