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Triangle xyz  is equilateral, with o  as its center. A point p is chosen at random, inside the triangle. Find the probability that point p is closer to point o than to any of the vertices. (In other words, find the probability that xp is shorter  than  zp and yp )

 Jun 19, 2020
 #1
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Using a geometric probability approach, the answer is 5/9.

 Jun 19, 2020
 #2
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Approximately  93.74/140.73 = 66.6%

 

 Jun 19, 2020

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