+37084 If you ignore wall friction , you will need TWO tubes that total the same AREA as the 5" tube
Area of 5" tube = pi r^2 = pi (2.5)^2 = 19.63 sq in
Two tubes, each would have to equal 19.63/2 sq in = 9.82 sq in
pi r^2 = 9.82 results in r = 1.768 inches..... 2 r = diameter = 3.54 inch diameter each
