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\(\text{Suppose the decimal } 0.28 \text{ is equal to } \frac{1}{n}+\frac{2}{n^2}, \text{ where } n \text{ is negative Find } n.\)

 Oct 9, 2020
 #1
avatar+27725 
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Multiply thru by n^2 to get

 

.28 n^2 = n +2    re-arrange

.28n^2 - n -2 = 0    Quadratic formula (for the negative value)    n = - 1.42857

 Oct 9, 2020

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