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4/3+3m/5=41/15
 Sep 3, 2013
 #1
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4/3+3m/5=41/15. Note that the both items of the left side can be reduced to the common denominator 15. (20 + 9m)/15 = 41/15. Breaking free of the denominator by multiplying both sides by 15 we get 20 + 9m = 41 => 9m = 21 =>m = 21/9 = 7/3

[input]solve(4/3+3*m/5=41/15, m)[/input]
 Sep 3, 2013
 #2
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scrutinizer:

4/3+3m/5=41/15. Note that the both items of the left side can be reduced to the common denominator 15. (20 + 9m)/15 = 41/15. Breaking free of the denominator by multiplying both sides by 15 we get 20 + 9m = 41 => 9m = 21 =>m = 21/9 = 7/3

[input]solve(4/3+3*m/5=41/15, m)[/input]


thanks
 Sep 3, 2013

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