The polynomial f(x) has degree 3. If f(0) = 4, f(1)= -2 , f(3) = 0, and f(3) = 28, then what are the x -intercepts of the graph of f(x)?
We have a problem here
f(3) = 0 and f (3) = 28
This is impossible......this would not be function because it does not pass the vertical line test......but a polynomial is always a function
