+257 2^(2x+1)=512 how do you solve?
I have
2=2
2=4
2=8
2=16
2=32
2=64
2=128
2=512
+36915 Take the LOG of both sides to get:
(2x+1) Log2 = log 512
2x+1 = log512/log2 = 9
2x=8
x=4
Doing it your way
2^1 = 2
2^2=4
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2^8 = 256 (you forgot this one)
2^9 = 512 so 2x+1 = 9 x = 4
+36915 Take the LOG of both sides to get:
(2x+1) Log2 = log 512
2x+1 = log512/log2 = 9
2x=8
x=4
Doing it your way
2^1 = 2
2^2=4
.
.
.
2^8 = 256 (you forgot this one)
2^9 = 512 so 2x+1 = 9 x = 4
