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avatar+171 

2^(2x+1)=512 how do you solve?

I have 

2=2

2=4

2=8

2=16

2=32

2=64

2=128

2=512

 Nov 6, 2018

Best Answer 

 #1
avatar+17209 
+3

Take the LOG of both sides to get:

(2x+1) Log2 = log 512

2x+1 = log512/log2 = 9

2x=8

x=4

 

Doing it your way

2^1 = 2

2^2=4

.

.

.

2^8 = 256    (you forgot this one)

2^9 = 512       so 2x+1 = 9     x = 4

 Nov 7, 2018
edited by ElectricPavlov  Nov 7, 2018
 #1
avatar+17209 
+3
Best Answer

Take the LOG of both sides to get:

(2x+1) Log2 = log 512

2x+1 = log512/log2 = 9

2x=8

x=4

 

Doing it your way

2^1 = 2

2^2=4

.

.

.

2^8 = 256    (you forgot this one)

2^9 = 512       so 2x+1 = 9     x = 4

ElectricPavlov Nov 7, 2018
edited by ElectricPavlov  Nov 7, 2018
 #2
avatar+171 
+1

Double Thanks! and I have heard of logarithms but we haven't used them yet

SydSu22  Nov 7, 2018

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