2^(2x+1)=512 how do you solve?

I have

2=2

2=4

2=8

2=16

2=32

2=64

2=128

2=512

SydSu22 Nov 6, 2018

#1**0 **

Take the LOG of both sides to get:

(2x+1) Log2 = log 512

2x+1 = log512/log2 = 9

2x=8

x=4

Doing it your way

2^1 = 2

2^2=4

.

.

.

2^8 = 256 (you forgot this one)

2^9 = 512 so 2x+1 = 9 x = 4

ElectricPavlov Nov 7, 2018

#1**0 **

Best Answer

Take the LOG of both sides to get:

(2x+1) Log2 = log 512

2x+1 = log512/log2 = 9

2x=8

x=4

Doing it your way

2^1 = 2

2^2=4

.

.

.

2^8 = 256 (you forgot this one)

2^9 = 512 so 2x+1 = 9 x = 4

ElectricPavlov Nov 7, 2018