Alg_2 Help

Simplify.

x^2/ x-1/ 3x^2/ x+4.

There is no brackets so your meaning if not clear but this is the question that you have asked.

$Simplify\\ x^2/ x-1/ 3x^2/ x+4\\ =(x^2/ x)\quad- ((1/ 3)x^2)/ x)\quad+4\\ =x \quad - \quad \frac{1x^2}{3}\div x\quad +4\\ =x \quad - \quad \frac{1x^2}{3x}\quad +4\\ =x \quad - \quad \frac{x}{3}\quad +4\\ =\frac{2x}{3}+4\\ =\frac{2x+12}{3}$