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Sophie and Simon are peeling a pile of potatoes for lunch in the cafeteria. Sophie can peel all the potatoes by herself in 45 minutes, while it would take Simon 30 minutes to do the job working alone. If Sophie and Simon work together to peel the potatoes, how long will it take them?

 Oct 6, 2015

Best Answer 

 #2
avatar+130536 
+5

Sophie does 1/45 of the job in one minute and Simon does 1/30 of the job in one minute.....let x be the time it takes to do the job [in minutes]  working together....and we have......

 

(1/45)x  + (1/30)x   = 1   .....  where "1"  represents the completed job......getting a common denominator, we have

 

[30 + 45]x / 1350  = 1   simplify

 

(75/ 1350)x  = 1     multiply both sides by 1350/75  and we have

 

x = 1350/75 =  18 minutes

 

 

 

cool cool cool

 Oct 6, 2015
 #1
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+5

Call the job of potato peeling 'x'    't' is the new time to do 'x'

Then Sophie's speed is  x/45    and  Simons speed is  x/30     

(x/45)t + (x/30)t = x

t(2x/90 + 3x/90) = x

t5x/90 =x

t5/90=1

t=90/5

t=18 minutes

 Oct 6, 2015
 #2
avatar+130536 
+5
Best Answer

Sophie does 1/45 of the job in one minute and Simon does 1/30 of the job in one minute.....let x be the time it takes to do the job [in minutes]  working together....and we have......

 

(1/45)x  + (1/30)x   = 1   .....  where "1"  represents the completed job......getting a common denominator, we have

 

[30 + 45]x / 1350  = 1   simplify

 

(75/ 1350)x  = 1     multiply both sides by 1350/75  and we have

 

x = 1350/75 =  18 minutes

 

 

 

cool cool cool

CPhill Oct 6, 2015
 #3
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0

In 1 minute Sophie does 1/45 of the job.

In 1 minute Simon does 1/30 of the job.

Their combined rates is 1/45 + 1/30=1/18 of the work done in 1 minute.

Therefore the whole combined work would be finished in 18 minutes.

 Oct 6, 2015

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