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algebra 1

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774

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how would you simplify the square root of 128?

Guest Mar 30, 2017

2⁺⁰ Answers

+9488

+3

$\sqrt{128}\\=\sqrt{2*2*2*2*2*2*2}\\=\sqrt{2*2}*\sqrt{2*2}*\sqrt{2*2}*\sqrt{2}\\=2*2*2*\sqrt2\\=8\sqrt{2}$

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hectictar Mar 30, 2017

+118696

+2

OR

$\sqrt{128}=\sqrt{64}*\sqrt{2}=8\sqrt2$

Melody Mar 30, 2017

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