how would you simplify the square root of 128?
\(\sqrt{128}\\=\sqrt{2*2*2*2*2*2*2}\\=\sqrt{2*2}*\sqrt{2*2}*\sqrt{2*2}*\sqrt{2}\\=2*2*2*\sqrt2\\=8\sqrt{2}\)
OR
\(\sqrt{128}=\sqrt{64}*\sqrt{2}=8\sqrt2\)
