+537 how do you find the square root/(cubbed root?) of 27
[3]27? I know the answer is 3 but I don't get how to find the answer
x^2 = x * x
x^3 = x * x * x
x^4 = x * x * x * x
x^n = x * x * x... (n times)
the square root is the reverse of the square
3^2 = 3 * 3 = 9
4^2 = 4 * 4 = 16
5^2 = 5 * 5 = 25
sqrt(9) = 3 because 3^2 = 9
sqrt(16) = 4 because 4^2 = 16
sqrt(25) = 5 because 5^2 = 25
technically, sqrt(9) = +/- 3 because 3 * 3 = 9 and -3 * -3 = 9
the cube root is the reverse of the cube (a cube is x^3 = x * x * x)
cbrt(27) = 3 because 3^3 = 3 * 3 * 3 = 27
cbrt(64) = 4 because 4^3 = 4 * 4 * 4 = 64
cbrt(125) = 5 because 5^3 = 5 * 5 * 5 = 125
