I dont know how to factore completely the equation below if someone could help me that will be such a great help :)

**10x ^{3}+20x^{2}+2x+4**

TerrificDawn Nov 8, 2018

#1**+3 **

10x^3 + 20x^2 + 2x + 4 factor by grouping

10x^2 ( x + 2) + 2 ( x + 2)

(x + 2) ( 10x^2 + 2)

(x + 2) * 2( 5x^2 + 1)

2 ( 5x^2 + 1) ( x + 2)

CPhill Nov 8, 2018

#2**0 **

Group the first two together and the second two together. For the first group, factor out 10x^{2} and for the second group, factor out 2.

10x^{3} + 20x^{2} + 2x + 4

10x^{3} + 20x^{2 }2x + 4

10x^{2} (x + 2) 2 (x + 2)

Now the factors in the parenthases are the same.

(10x^{2} + 2) (x + 2)

2(5x^{2} + 1) (x + 2)

Guest Nov 8, 2018