We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
420
1
avatar

Algebra 2 help: functions

 Oct 12, 2017
 #1
avatar+104712 
+2

 

Leading coefficient 2, zeroes   =  2, √2, -√2

 

So...we can write this as

 

2 ( x - 2) (x - √2) (x + √2)  =

2(x - 2) (x^2  - 2)  =

2 (x^3 - 2x^2 - 2x + 4)  =

2x^3 - 4x^2 - 4x + 8

 

Similarly....we have

 

Leading coefficient -1, zeroes   =  1, 1 +√3,  1-√3

 

-1 ( x -1) ( x - [1 +√3] ) ( x  - [ 1 -√3] )  =

-1 (x - 1) ( x^2  - [ 1 + √3]x  - [ 1 -√3] x  +  [1 +√3] [1 -√3] )  =

-1 (x - 1) (x^2 - x - √3x  - x + √3x  + 1  - 3 )  =

-1 (x - 1)  (x^2 - 2x -2)  =

-1( x^3 -x^2 - 2x^2 + 2x - 2x + 2) =

-1 (x^3 - 3x^2 + 2) =

-x^3 + 3x^2 - 2

 

 

cool cool cool

 Oct 12, 2017

11 Online Users

avatar