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7.

 Jan 29, 2018
 #1
avatar+111331 
0

1.  Minimum value  is   2.5

 

2.  Period  =  6pi      Amplitude = 5      Midline :  y  = -2 

 

Since we have a y intercept of  (0, -2)  the sine function seems he best choice...here's the function :

 

y  =  5sin (x /3 )  - 2

 

Here's the graph : https://www.desmos.com/calculator/shtgla34yy

 

 

cool cool cool

 Jan 29, 2018
 #2
avatar+111331 
0

3.

 

Reflected over the x axis gives us  y  = -cos (x)

 

Shifted down 2 units gives  y  =  -cos(x) - 2 = g(x)

 

 

cool cool cool

 Jan 29, 2018
 #3
avatar+111331 
0

4.      f(x)  =  (1/2)cos ( x)  +  5

 

The "1/2 "  does not affect the midline..it only halves the normal amplitude

 

The "5" shifts  the normal cosine graph up 5 uints

 

So....the midline  is   y = 5

 

Here's the graph : https://www.desmos.com/calculator/lkmkkpvrzq

 

 

cool cool cool

 Jan 29, 2018
 #4
avatar+111331 
0

5.   

 

We can solve for the period, p,  as follows

 

(1/4) p  = 2pi      multiply both sides by 4

 

p   =  8 pi

 

 

The frequency  =  1 / period  =    1  / [ 8 pi ]  

 

 

cool cool cool

 Jan 29, 2018
 #5
avatar+111331 
0

6. The period is  pi / 2

 

7.  The graph is vertically stretched by a factor of 2  and shifted up 3 units

 

 

cool cool cool

 Jan 29, 2018

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