We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
1
212
2
avatar+299 

Q1)

Q2)

 

thank you (:

 Nov 9, 2018
 #1
avatar+5635 
+1

\(-1=\sqrt{3x-2}-\sqrt{4x+1}\\ \sqrt{4x+1}-1 = \sqrt{3x-2}\\ (4x+1)-2\sqrt{4x+1}+1 = 3x-2\\ 4x+2 - 2\sqrt{4x+1} = 3x-2\\ x+4=2\sqrt{4x+1}\\ x^2+8x+16 = 4(4x+1) = 16x+4\\ x^2 -8x + 12 = 0\\ (x-6)(x-2) = 0\\ x=6,~2\)

 

Let's check these solutions

 

\(\sqrt{18-2} - \sqrt{24+5} = 4 - 5 = -1\\ \sqrt{6-2}-\sqrt{8+1} = 2-3 = -1\)

 

Both solutions are valid.

 Nov 9, 2018
 #2
avatar+5635 
+1

\(\dfrac{\dfrac{4}{2x-1}+\dfrac 1 4}{x+1}=\)

 

 

\(\dfrac{\dfrac{4\cdot 4 + 2x-1}{4(2x-1)}}{x+1} =\)

 

 

\(\dfrac{15+2x}{4(2x-1)(x+1)}\)

.
 Nov 9, 2018

4 Online Users