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# Algebra 2 help!

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The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a

standard deviation of 53. Jill picked 276 huckleberries in the contest.

What percent of huckleberries picked less than Jill?

a. 24%

b. 33%

c.45%

d.52%

Apr 4, 2019

$$p=\Phi\left(\dfrac{276-300}{53}\right) =\\ \Phi(-0.45283)= \text{ (using software or lookup table)}\\ 0.325 =32.5\%$$