Algebra 2 help

x + 5y  = -15

y  = (1/5) x + 1        sub the second into the first for y  and we have

x + 5 ( 1/5 x + 1)  = -15

x + x + 5  = -15

2x + 5  = -15     subtract 5 from  both sides

2x  = -20     divide both sides by 2

x  = -10

And using    y  = (1/5)x + 1  to find  x, we have   y  =(1/5) (-10) + 1  = -2 + 1   =  -1

So   (x , y)   = ( -10 , -1)

x + y  = 6

x  =  y + 4        sub the second into the first for  x

(y + 4) + y  = 6

2y + 4  = 6

2y  = 2

y = 1

And   x   =  y + 4  =  1 + 4   = 5

So   (x, y)  = ( 5 , 1)

2x - 3y  = -27     multiply through by 3   ⇒   6x - 9y = -81    (1)

-3x + 2y  = 23   multiply through  by  2 ⇒   -6x + 4y  =  46    (2)

Add (1)  and (2)  and we get

-5y  = -35     divide both sides by  -5

y  = 7

And  using   2x  -  3y = -27  to  find x we get

2x - 3(7)  = -27

2x - 21  = -27     add 21 to  both sides

2x = -6    divide both sids by  2

x  = -3

So  (x ,y )  =  ( -3, 7)

Last one

x + 3y - z  = 6    

4x - 2y + 2z = -10    

6x + z  = -12

Sorry..Johnny...but I gotta' go in just a minute

The answer to  this is   (x ,y , z)   = ( -3, 5, 6)

When I get back on...I'll give you a complete run through...if you need it  !!!