write an equation in slope intercept form that is perpendicular to y=3x-2 and passes through ( 6, -1)
+23251 Equation: y = 3x - 2
This equation has slope = 3.
The equation of any line perpendicular to this line will have a slope of -1/3 (the negative reciprocal).
The point-slope form of a line is: y - y1 = m(x - x1) where m is the slope and (x1, y1) is the known point:
---> y - -1 = (-1/3)(x - 6)
---> y + 1 = (-1/3)(x - 6)
---> 3(y + 1) = -1(x - 6)
---> 3y + 3 = -x + 6
---> 3y = -x + 3
---> y = (-1/3)x + 1
