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Algebra 2 question

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Given a, b, and c are positive integers greater than 2 what are all the possible values of a*b*c given a*b*c=5(a-2)(b-2)(c-2).

Dec 9, 2023

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Since the original expression is 5 times an integer, abc must be an integer, as well. We can factorize the original expression to get 5(a+2)(b+2)(c+2), so abc=5(a+2)(b+2)(c+2), and we need to find the possible values for 5(a+2)(b+2)(c+2).

If any of a+2, b+2, c+2 is equal to 1, then abc is equal to 5. Since a, b, and c are integers, we know that 5=5(a+2)(b+2)(c+2) is the only case where abc is equal to 5.

If any of a+2, b+2, c+2 is equal to 2, then abc is equal to 10. Since a, b, and c are integers, we know that 10=5(a+2)(b+2)(c+2) is the only case where abc is equal to 10.

If any of a+2, b+2, c+2 is equal to 5, then abc is equal to 50. Since a, b, and c are integers, we know that 50=5(a+2)(b+2)(c+2) is the only case where abc is equal to 50.

If all of a+2, b+2, c+2 are equal to 3, then abc is equal to 125. Since a, b, and c are integers, we know that 125=5(a+2)(b+2)(c+2) is the only case where abc is equal to 125.

Therefore, the possible values for abc are 0,5,10,50,125​.

Dec 9, 2023