The table shows ordered pairs for a polynomial function, f.

x f(x)

−3 −32

−2 −9

−1 0

0 1

1 0

2 3

3 16

What is the degree of f?

I need help understanding this. Do I have to graph? How do I solve this.

Jazminfun0128182 Oct 16, 2018

#1**+1 **

You will find f(x) its

\(f(x) = x^3 - x^2 - x +1 \)

But where i find it?

You will start for 0 so f(0)= 1 so its a fuction function with +1 in the end because all other is 0

after for experience see that when you have 2 f(2)= 3 but f(-2) = -9 and 9>3 so you have x^3 but 2 in row 2 (-) and with tests resulting

\(f(x) = x^3 - x^2 - x +1\)

and with this equation verifies this :−3 −32,−2 −9,−1 0,0 1,1 0,2 3 ,3 16

so the question is What is the degree of f?

The degree of f(x) = 3 because is x^3 !!!

Hope it helps!

Dimitristhym Oct 16, 2018