+0  
 
0
347
2
avatar+154 

The table shows ordered pairs for a polynomial function, f. 



x f(x)
−3 −32
−2 −9
−1 0
0 1
1 0
2 3
3 16
What is the degree of f?



I need help understanding this. Do I have to graph? How do I solve this.

 Oct 16, 2018
 #1
avatar+316 
+2

You will find f(x) its 

\(f(x) = x^3 - x^2 - x +1 \)

But where i find it? 

You will start for 0 so f(0)= 1 so its a fuction function with +1 in the end because all other is 0 

after for experience see that when you have 2 f(2)= 3 but f(-2) = -9 and 9>3 so you have x^3 but 2 in row 2 (-) and with tests resulting 

\(f(x) = x^3 - x^2 - x +1\)

and with this equation verifies this :−3 −32,−2 −9,−1 0,0 1,1 0,2 3 ,3 16 

so the question is What is the degree of f? 

The degree of f(x) = 3 because is x^3 !!!

Hope it helps! 

 Oct 16, 2018
 #2
avatar
0

Thank you for the answer. Still a little confused though sorry but do I have to plug in the numbers in the equation you gave me. I know the number for (f)x but do i have to put the number like -3 for all of the missing x's

Guest Oct 18, 2018

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