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# Algebra 2 question

0
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The table shows ordered pairs for a polynomial function, f.

x f(x)
−3 −32
−2 −9
−1 0
0 1
1 0
2 3
3 16
What is the degree of f?

I need help understanding this. Do I have to graph? How do I solve this.

Oct 16, 2018

#1
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+2

You will find f(x) its

\(f(x) = x^3 - x^2 - x +1 \)

But where i find it?

You will start for 0 so f(0)= 1 so its a fuction function with +1 in the end because all other is 0

after for experience see that when you have 2 f(2)= 3 but f(-2) = -9 and 9>3 so you have x^3 but 2 in row 2 (-) and with tests resulting

\(f(x) = x^3 - x^2 - x +1\)

and with this equation verifies this :−3 −32,−2 −9,−1 0,0 1,1 0,2 3 ,3 16

so the question is What is the degree of f?

The degree of f(x) = 3 because is x^3 !!!

Hope it helps!

Oct 16, 2018
#2
0

Thank you for the answer. Still a little confused though sorry but do I have to plug in the numbers in the equation you gave me. I know the number for (f)x but do i have to put the number like -3 for all of the missing x's

Guest Oct 18, 2018