+168 The table shows ordered pairs for a polynomial function, f.
x f(x)
−3 −32
−2 −9
−1 0
0 1
1 0
2 3
3 16
What is the degree of f?
I need help understanding this. Do I have to graph? How do I solve this.
+343 You will find f(x) its
\(f(x) = x^3 - x^2 - x +1 \)
But where i find it?
You will start for 0 so f(0)= 1 so its a fuction function with +1 in the end because all other is 0
after for experience see that when you have 2 f(2)= 3 but f(-2) = -9 and 9>3 so you have x^3 but 2 in row 2 (-) and with tests resulting
\(f(x) = x^3 - x^2 - x +1\)
and with this equation verifies this :−3 −32,−2 −9,−1 0,0 1,1 0,2 3 ,3 16
so the question is What is the degree of f?
The degree of f(x) = 3 because is x^3 !!!
Hope it helps!
