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If 10k = 64, what is the value of \(10^ {{k \over 2} + 1}\)? Answer without using log.

 Dec 27, 2017

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 #1
avatar+103678 
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If \(10^k = 64\), what is the value of \(10^ {{k \over 2} + 1}\)?   Answer without using log.

 

 

\(10^{\frac{k}{2}+1}\\ =10^1*10^{\frac{k}{2}}\\ =10*(10^k)^{\frac{1}{2}}\\ =10*(64)^{\frac{1}{2}}\\ =10*8\\ =80\)

.
 Dec 27, 2017
 #1
avatar+103678 
+3
Best Answer

If \(10^k = 64\), what is the value of \(10^ {{k \over 2} + 1}\)?   Answer without using log.

 

 

\(10^{\frac{k}{2}+1}\\ =10^1*10^{\frac{k}{2}}\\ =10*(10^k)^{\frac{1}{2}}\\ =10*(64)^{\frac{1}{2}}\\ =10*8\\ =80\)

Melody Dec 27, 2017

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