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# Algebra 2/Trig

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If 10k = 64, what is the value of $$10^ {{k \over 2} + 1}$$? Answer without using log.

Dec 27, 2017

#1
+99282
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If $$10^k = 64$$, what is the value of $$10^ {{k \over 2} + 1}$$?   Answer without using log.

$$10^{\frac{k}{2}+1}\\ =10^1*10^{\frac{k}{2}}\\ =10*(10^k)^{\frac{1}{2}}\\ =10*(64)^{\frac{1}{2}}\\ =10*8\\ =80$$

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Dec 27, 2017

#1
+99282
+3
If $$10^k = 64$$, what is the value of $$10^ {{k \over 2} + 1}$$?   Answer without using log.
$$10^{\frac{k}{2}+1}\\ =10^1*10^{\frac{k}{2}}\\ =10*(10^k)^{\frac{1}{2}}\\ =10*(64)^{\frac{1}{2}}\\ =10*8\\ =80$$