If 10k = 64, what is the value of \(10^ {{k \over 2} + 1}\)? Answer without using log.
If \(10^k = 64\), what is the value of \(10^ {{k \over 2} + 1}\)? Answer without using log.
\(10^{\frac{k}{2}+1}\\ =10^1*10^{\frac{k}{2}}\\ =10*(10^k)^{\frac{1}{2}}\\ =10*(64)^{\frac{1}{2}}\\ =10*8\\ =80\)
