#1**0 **

First lets remeber the rule a*logb=logb^a

3log7= log7^3

2log5=log5^2

4log2=log2^4

we can write this as

log7^3+log5^2-log2^4

log(7^3+5^2)/(log2^4) [we can do this becuase of these rules loga^x+loga^y=loga^(x*y) and loga^x-loga(y)=loga(x/y))

log(7^3+5^2)/(log2^4)= __log(8575/16) which would be your solution in single log form.__ Hope this helped!

ChessChris Mar 8, 2023