+34 First lets remeber the rule a*logb=logb^a
3log7= log7^3
2log5=log5^2
4log2=log2^4
we can write this as
log7^3+log5^2-log2^4
log(7^3+5^2)/(log2^4) [we can do this becuase of these rules loga^x+loga^y=loga^(x*y) and loga^x-loga(y)=loga(x/y))
log(7^3+5^2)/(log2^4)= log(8575/16) which would be your solution in single log form. Hope this helped!
