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What is the solution to the system of equations?

{−2x+6y=−38

3x−4y=32

Guest Aug 29, 2018

Best Answer 

 #1
avatar+2983 
+3

What happens if you multiply the first equation by -3 and the second equation by 2? Let's try it!

 

If we follow what I said, we will get: 6x+-18y=114 and 6x-8y=64. Now, we can subtract, to attain -10y=50, so y=-5. We can plug the value of y back in the second equation, to get: 3x-4(-5)=32, 3x+20=32, 3x=12, x=4. Thus, the answer is : (4,-5).

tertre  Aug 29, 2018
 #1
avatar+2983 
+3
Best Answer

What happens if you multiply the first equation by -3 and the second equation by 2? Let's try it!

 

If we follow what I said, we will get: 6x+-18y=114 and 6x-8y=64. Now, we can subtract, to attain -10y=50, so y=-5. We can plug the value of y back in the second equation, to get: 3x-4(-5)=32, 3x+20=32, 3x=12, x=4. Thus, the answer is : (4,-5).

tertre  Aug 29, 2018
 #2
avatar+88775 
+3

Good job, tertre  !!!

 

 

cool cool cool

CPhill  Aug 29, 2018
 #3
avatar+2983 
+3

Thank you, CPhill! smiley

tertre  Aug 29, 2018

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