The graph of the function f(x) = x^3 – 7x – 6 intersects the x-axis at the points (–2, 0), (–1, 0), and (3, 0) as shown. Which expression is equivalent to x^3 – 7x – 6?

Answer choices:

A) (x – 1)(x – 2)(x – 3)

B) (x – 1)(x + 2)(x – 3)

C) (x + 1)(x – 2)(x – 3)

D) (x + 1)(x + 2)(x – 3)

**Note**: Screenshot above regarded to this question

Cupcake Dec 18, 2018

edited by
Guest
Dec 18, 2018

#1**+2 **

For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 ) i.e. f(x) =0

then "D"

f(x)= 0 = (x+1) (x+2)(x-3) So at least ONE of the factors must equal 0

(x+1) = 0 would mena x = -1

(x+2) = 0 would mean x = -2

(x-3) = 0 would mean x = 3 so answer D

ElectricPavlov Dec 18, 2018

#1**+2 **

Best Answer

For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 ) i.e. f(x) =0

then "D"

f(x)= 0 = (x+1) (x+2)(x-3) So at least ONE of the factors must equal 0

(x+1) = 0 would mena x = -1

(x+2) = 0 would mean x = -2

(x-3) = 0 would mean x = 3 so answer D

ElectricPavlov Dec 18, 2018