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The graph of the function f(x) = x^3 – 7x – 6 intersects the x-axis at the points (–2, 0), (–1, 0), and (3, 0) as shown. Which expression is equivalent to x^3 – 7x – 6?

 

http://prntscr.com/lwmejz

 

Answer choices:

A) (x – 1)(x – 2)(x – 3)

B) (x – 1)(x + 2)(x – 3)

C) (x + 1)(x – 2)(x – 3)

D) (x + 1)(x + 2)(x – 3)

 

Note: Screenshot above regarded to this question

 Dec 18, 2018
edited by Guest  Dec 18, 2018

Best Answer 

 #1
avatar+18873 
+2

For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 )  i.e.  f(x) =0

 

then   "D"

f(x)= 0 =  (x+1) (x+2)(x-3)     So at least ONE of the factors must equal 0

               (x+1) = 0      would mena x = -1

                         (x+2) = 0    would mean   x = -2

                                 (x-3) = 0 would mean    x = 3      so answer D

 Dec 18, 2018
 #1
avatar+18873 
+2
Best Answer

For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 )  i.e.  f(x) =0

 

then   "D"

f(x)= 0 =  (x+1) (x+2)(x-3)     So at least ONE of the factors must equal 0

               (x+1) = 0      would mena x = -1

                         (x+2) = 0    would mean   x = -2

                                 (x-3) = 0 would mean    x = 3      so answer D

ElectricPavlov Dec 18, 2018

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