The graph of the function f(x) = x^3 – 7x – 6 intersects the x-axis at the points (–2, 0), (–1, 0), and (3, 0) as shown. Which expression is equivalent to x^3 – 7x – 6?
Answer choices:
A) (x – 1)(x – 2)(x – 3)
B) (x – 1)(x + 2)(x – 3)
C) (x + 1)(x – 2)(x – 3)
D) (x + 1)(x + 2)(x – 3)
Note: Screenshot above regarded to this question
For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 ) i.e. f(x) =0
then "D"
f(x)= 0 = (x+1) (x+2)(x-3) So at least ONE of the factors must equal 0
(x+1) = 0 would mena x = -1
(x+2) = 0 would mean x = -2
(x-3) = 0 would mean x = 3 so answer D
For the value of 'y' to equal ZERO (all of the points are x-intercepts and thus = 0 ) i.e. f(x) =0
then "D"
f(x)= 0 = (x+1) (x+2)(x-3) So at least ONE of the factors must equal 0
(x+1) = 0 would mena x = -1
(x+2) = 0 would mean x = -2
(x-3) = 0 would mean x = 3 so answer D