#2**+2 **

One way to do this is to pick a point in the each shaded region and see if that point satisifies all three inequalities

So....in the top left graph, let's just choose a point, say (1,0) = (x, y)

So

0 - 1 ≤ 4(1) is true

1 + 0 > - 4 is true

0 ≤ (1/3) (1) is true

So....as Penquino found.....the top left graph is correct !!!!

CPhill Dec 21, 2018